Tiling a Polyabolo at Scale 2 with Two Tetraboloes

  • Introduction
  • Table
  • Solutions
  • Holeless Variants
  • Introduction

    A tetrabolo is a figure made of four isosceles right triangles joined edge to edge. There are 14 such figures, not distinguishing reflections and rotations.

    Here I study the problem of arranging copies of two tetraboloes to form some polyabolo that has been scaled up by a factor of 2.

    See also

  • Tiling a Polyomino at Scale 2 with Two Pentominoes
  • Tiling a Polyomino at Scale 2 with a Tetromino and a Pentomino
  • Tiling a Polyiamond at Scale 2 with Two Hexiamonds
  • Table of Results

    This table shows the smallest total number of copies of two tetraboloes known to be able to tile some polyabolo enlarged by a scale factor of 2, using at least one copy of each tetrabolo.

    The blue indexes are links to tilings by the specified tetrabolo alone.

    ACDGIJKLORSVYZ
    A* 10 5 5 3 5 20 3 5 5 ? 12 16 3
    C10 * 8 16 6 8 8 6 ? 8 20 24 6 6
    D5 8 * 6 6 2 4 6 8 8 6 8 7 4
    G5 16 6 * ? 4 6 6 4 8 10 8 5 6
    I3 6 6 ? * 6 6 4 ? 6 ? ? 6 4
    J5 8 2 4 6 * 4 6 4 4 10 8 3 6
    K20 8 4 6 6 4 * 6 28 8 ? 12 12 4
    L3 6 6 6 4 6 6 * 6 6 ? ? 4 4
    O5 ? 8 4 ? 4 28 6 * 8 ? 8 ? 6
    R5 8 8 8 6 4 8 6 8 * 20 6 8 6
    S? 20 6 10 ? 10 ? ? ? 20 * ? ? ?
    V12 24 8 8 ? 8 12 ? 8 6 ? * ? 4
    Y16 6 7 5 6 3 12 4 ? 8 ? ? * ?
    Z3 6 4 6 4 6 4 4 6 6 ? 4 ? *

    Solutions

    So far as I know, these solutions use as few tiles as possible. They are not necessarily uniquely minimal.

    2 Tiles

    3 Tiles

    4 Tiles

    5 Tiles

    6 Tiles

    7 Tiles

    8 Tiles

    10 Tiles

    12 Tiles

    16 Tiles

    20 Tiles

    24 Tiles

    28 Tiles

    Holeless Variants

    Last revised 2025-05-05.


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    Col. George Sicherman [ HOME | MAIL ]